2005 AMC 12B Problem 5

Below is the professionally curated solution for Problem 5 of the 2005 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 12B solutions, or check the answer key.

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Concepts:circle areaarea

Difficulty rating: 1130

5.

An 88-foot by 1010-foot floor is tiled with square tiles of size 11 foot by 11 foot. Each tile has a pattern consisting of four white quarter circles of radius 12\dfrac12 foot centered at each corner of the tile. The remaining portion of the tile is shaded. How many square feet of the floor are shaded?

8020π80 - 20\pi

6010π60 - 10\pi

8010π80 - 10\pi

60+10π60 + 10\pi

80+10π80 + 10\pi

Solution:

The four quarter circles in a tile together form one full circle of radius 12,\dfrac12, with area π(12)2=π4.\pi\left(\dfrac12\right)^2 = \dfrac{\pi}{4}.

So each tile has shaded area 1π41 - \dfrac{\pi}{4} square feet.

There are 810=808 \cdot 10 = 80 tiles, so the total shaded area is 80(1π4)=8020π. 80\left(1 - \dfrac{\pi}{4}\right) = 80 - 20\pi.

Thus, the correct answer is A.

Problem 5 in Other Years