2002 AMC 12B Problem 5

Below is the professionally curated solution for Problem 5 of the 2002 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 12B solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:angle sumarithmetic sequence

Difficulty rating: 1080

5.

Let v,v, w,w, x,x, y,y, and zz be the degree measures of the five angles of a pentagon. Suppose v<w<x<y<zv\lt w\lt x\lt y\lt z and v,v, w,w, x,x, y,y, zz form an arithmetic sequence. Find the value of x.x.

7272

8484

9090

108108

120120

Solution:

The five interior angles sum to 540.540^\circ. Writing the sequence as x2d,x-2d, xd,x-d, x,x, x+d,x+d, x+2d,x+2d, the sum is 5x=540,5x=540, so x=108.x=108.

Thus, the correct answer is D.

Problem 5 in Other Years