2024 AMC 12B Problem 5

Below is the professionally curated solution for Problem 5 of the 2024 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 12B solutions, or check the answer key.

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Concepts:arithmetic sequenceoptimization

Difficulty rating: 1340

5.

In the following expression, Melanie changed some of the plus signs to minus signs:

1+3+5+7++97+991 + 3 + 5 + 7 + \cdots + 97 + 99

When the new expression was evaluated, it was negative. What is the least number of plus signs that Melanie could have changed to minus signs?

1414

1515

1616

1717

1818

Solution:

The original expression sums the first 5050 odd numbers, giving 502=2500.50^2 = 2500. Changing a term of value vv from ++ to - decreases the total by 2v,2v, so to make the result negative the flipped terms must total more than 25002=1250.\dfrac{2500}{2} = 1250.

To use as few terms as possible, flip the largest odd numbers 99,97,95,99, 97, 95, \ldots The largest kk of them sum to k(100k).k(100 - k). With k=14k = 14 this is 1486=12041250,14 \cdot 86 = 1204 \le 1250, but with k=15k = 15 it is 1585=1275>1250.15 \cdot 85 = 1275 \gt 1250. So 1515 sign changes suffice and 1414 do not.

Thus, the correct answer is B.

Problem 5 in Other Years