2002 AMC 12A 第 11 题

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11.

Earl E. Bird 先生每天上午八点整离家上班。当他的平均速度为每小时 4040 英里时,会晚到三分钟;当平均速度为每小时 6060 英里时,会早到三分钟。Bird 先生应以多少英里每小时的平均速度行驶,才能准时到达工作地点?

Mr. Earl E. Bird leaves his house for work at exactly 8:00 A.M. every morning. When he averages 4040 miles per hour, he arrives at his workplace three minutes late. When he averages 6060 miles per hour, he arrives three minutes early. At what average speed, in miles per hour, should Mr. Bird drive to arrive at his workplace precisely on time?

4545

4848

5050

5555

5858

答案:B
知识点:路程、速度与时间方程组
难度评级:1380
解答:

设准时所需时间为 tt 小时。三分钟是 0.050.05 小时,所以 40(t+0.05)=60(t0.05)40(t+0.05) = 60(t-0.05)

40t+2=60t340t + 2 = 60t - 3, 所以 t=0.25t = 0.25。 路程为 40(0.25+0.05)=1240(0.25+0.05) = 12 英里,所需速度为 120.25=48\dfrac{12}{0.25} = 48 英里每小时。

因此,正确答案是 B

Let tt be the time in hours to arrive on time. Since three minutes is 0.050.05 hours, 40(t+0.05)=60(t0.05).40(t+0.05) = 60(t-0.05).

This gives 40t+2=60t3,40t + 2 = 60t - 3, so t=0.25.t = 0.25. The distance is 40(0.25+0.05)=1240(0.25+0.05) = 12 miles, and the required speed is 120.25=48\dfrac{12}{0.25} = 48 miles per hour.

Thus, the correct answer is B.

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