2021 AMC 12A Fall 第 5 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

5.

鸸鹋 Elmer 在乡村道路上相邻两根电线杆之间行走需要 4444 个等长步幅。鸵鸟 Oscar 用 1212 个等长跃步可以走完同一距离。电线杆等距排列,这条路上的第 4141 根电线杆距离第一根电线杆正好一英里(52805280 英尺)。Oscar 的一个跃步比 Elmer 的一个步幅长多少英尺?

Elmer the emu takes 4444 equal strides to walk between consecutive telephone poles on a rural road. Oscar the ostrich can cover the same distance in 1212 equal leaps. The telephone poles are evenly spaced, and the 4141st pole along this road is exactly one mile (52805280 feet) from the first pole. How much longer, in feet, is Oscar's leap than Elmer's stride?

66

88

1010

1111

1515

答案:B
知识点:植树问题比与比例
难度评级:1270
解答:

第一根和第 4141 根电线杆之间有 4040 个间隔,所以每个间隔长 528040=132\dfrac{5280}{40} = 132 英尺。

Elmer 的步幅为 13244=3\dfrac{132}{44} = 3 英尺,Oscar 的跃步为 13212=11\dfrac{132}{12} = 11 英尺, 差为 113=811 - 3 = 8 英尺。

所以正确答案是 B

There are 4040 gaps between the first and 4141st poles, so each gap is 528040=132\dfrac{5280}{40} = 132 feet.

Elmer's stride is 13244=3\dfrac{132}{44} = 3 feet and Oscar's leap is 13212=11\dfrac{132}{12} = 11 feet, a difference of 113=811 - 3 = 8 feet.

Thus, the correct answer is B.

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