2018 AMC 12A Problem 2

Below is the professionally curated solution for Problem 2 of the 2018 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 12A solutions, or check the answer key.

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Concepts:optimizationcasework

Difficulty rating: 1020

2.

While exploring a cave, Carl comes across a collection of 55-pound rocks worth $1414 each, 44-pound rocks worth $1111 each, and 11-pound rocks worth $22 each. There are at least 2020 of each size. He can carry at most 1818 pounds. What is the maximum value, in dollars, of the rocks he can carry out of the cave?

4848

4949

5050

5151

5252

Solution:

The rocks are worth $2.80,2.80, $2.75,2.75, and $22 per pound respectively, so the 11-pound rocks are never worthwhile. Testing how many 55-pound rocks to take and filling the rest with 44-pound rocks: three 55-pound rocks plus three 11-pound rocks give $42+$6=$48;42 + \$6 = \$48; two 55-pound and two 44-pound rocks use all 1818 pounds for $28+$22=$50;28 + \$22 = \$50; one 55-pound, three 44-pound, and one 11-pound rock give $49.49.

The maximum value is $50.50. Thus, the correct answer is C.

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