2006 AMC 12A 第 12 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

12.

若干个相扣的环,每个厚 11 cm,挂在一个钉子上。最上面的环外径为 2020 cm。其余每个环的外径都比上方的环小 11 cm。最下面的环外径为 33 cm。从最上面环的顶部到最下面环的底部的距离是多少 cm?

A number of linked rings, each 11 cm thick, are hanging on a peg. The top ring has an outside diameter of 2020 cm. The outside diameter of each of the other rings is 11 cm less than that of the ring above it. The bottom ring has an outside diameter of 33 cm. What is the distance, in cm, from the top of the top ring to the bottom of the bottom ring?

171171

173173

182182

188188

210210

答案:B
知识点:等差数列求和
难度评级:1370
解答:

最上面的环跨越 2020 cm。下面每个环与上方的环重叠 22 cm(两倍的 11-cm 厚度),所以它增加的长度为外径减 22

下面各环外径为 19,18,,319, 18, \ldots, 3, 贡献 17,16,,117, 16, \ldots, 1。 因此总距离为 20+(17+16++1)=20+17182=20+153=173 cm. \begin{gathered} 20 + (17 + 16 + \cdots + 1) \\ = 20 + \frac{17 \cdot 18}{2} \\ = 20 + 153 \\ = 173 \text{ cm}. \end{gathered}

因此,正确答案是 B

The top ring spans 2020 cm. Each ring below overlaps the ring above by 22 cm (twice the 11-cm thickness), so it adds its outside diameter minus 2.2.

The lower rings have outside diameters 19,18,,3,19, 18, \ldots, 3, contributing 17,16,,1.17, 16, \ldots, 1. Thus the total distance is 20+(17+16++1)=20+17182=20+153=173 cm. \begin{gathered} 20 + (17 + 16 + \cdots + 1) \\ = 20 + \frac{17 \cdot 18}{2} \\ = 20 + 153 \\ = 173 \text{ cm}. \end{gathered}

Thus, the correct answer is B.

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