2021 AMC 12B Fall Problem 12

Below is the professionally curated solution for Problem 12 of the 2021 AMC 12B Fall, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Fall solutions, or check the answer key.

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Concepts:sum of factorsprime factorization

Difficulty rating: 1760

12.

For nn a positive integer, let f(n)f(n) be the quotient obtained when the sum of all positive divisors of nn is divided by n.n. For example, f(14)=(1+2+7+14)÷14=127.f(14) = (1 + 2 + 7 + 14) \div 14 = \dfrac{12}{7}. What is f(768)f(384)?f(768) - f(384)?

1768\dfrac{1}{768}

1192\dfrac{1}{192}

11

43\dfrac{4}{3}

83\dfrac{8}{3}

Solution:

Since 768=283,768 = 2^8 \cdot 3, its divisor sum is (291)(1+3)=5114=2044,(2^9 - 1)(1 + 3) = 511 \cdot 4 = 2044, so f(768)=2044768=511192.f(768) = \dfrac{2044}{768} = \dfrac{511}{192}.

Since 384=273,384 = 2^7 \cdot 3, its divisor sum is (281)(1+3)=2554=1020,(2^8 - 1)(1 + 3) = 255 \cdot 4 = 1020, so f(384)=1020384=510192.f(384) = \dfrac{1020}{384} = \dfrac{510}{192}.

The difference is 511510192=1192.\dfrac{511 - 510}{192} = \dfrac{1}{192}.

Thus, the correct answer is B.

Problem 12 in Other Years