2010 AMC 12A 第 2 题

先试着解答 2010 AMC 12A 第 2 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2010 AMC 12A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

2.

一艘渡船从上午 1010 点开始,每小时载游客去一座岛,最后一班在下午 33 点出发。某天船长注意到上午 1010 点那班有 100100 名游客,并且之后每一班的游客数都比前一班少 11 人。那天这艘渡船一共载了多少名游客到岛上?
A ferry boat shuttles tourists to an island every hour starting at 1010 am until its last trip, which starts at 33 pm. One day the boat captain notes that on the 1010 am trip there were 100100 tourists on the ferry boat, and that on each successive trip, the number of tourists was 11 fewer than on the previous trip. How many tourists did the ferry take to the island that day?
585585
594594
672672
679679
694694
答案:A
知识点:等差数列求和
小提示:
数一数从上午 1010 点到下午 33 点一共有多少班。
Count how many trips run from 1010 am through 33 pm
大提示:
各班人数为 100,99,…,95100,99,\ldots,95;把它们相加。
The trip counts are 100,99,…,95;100,99,\ldots,95; add them
解答:
渡船共有 66 班:1010 点、1111 点、1212 点、11 点、22 点和 33 点。
游客数分别为 100,99,98,97,96,95100,99,98,97,96,95,所以总数为 6⋅100−(1+2+3+4+5)=600−15=585。 \begin{gathered} 6\cdot100-(1+2+3+4+5) \\ =600-15 \\ =585 \end{gathered}\text{。}
所以正确答案是 A。
The ferry makes 66 trips: at 10,10, 11,11, 12,12, 1,1, 2,2, and 3.3.
The numbers of tourists are 100,99,98,97,96,95,100,99,98,97,96,95, so the total is 6⋅100−(1+2+3+4+5)=600−15=585. \begin{gathered} 6\cdot100-(1+2+3+4+5) \\ =600-15 \\ =585. \end{gathered}
Thus, A is the correct answer.
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