2011 AMC 12B 第 2 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

2.

Josanna 到目前为止的考试成绩是 9090808070706060, 和 8585。 她的目标是在下一次考试后, 把平均分至少提高 33 分。她下一次考试至少需要多少分才能达到目标?

Josanna's test scores to date are 90,90, 80,80, 70,70, 60,60, and 85.85. Her goal is to raise her test average at least 33 points with her next test. What is the minimum test score she would need to accomplish this goal?

8080

8282

8585

9090

9595

答案:E
知识点:平均数
难度评级:880
解答:

前五次总分为 90+80+70+60+85=38590+80+70+60+85=385,平均分为 7777。目标是新的平均分至少为 8080

六次考试平均 8080 分需要总分 680=4806\cdot80=480,因此第六次至少需要 480385=95480-385=95

所以正确答案是 E

The five scores sum to 90+80+70+60+85=385,90+80+70+60+85=385, giving an average of 77.77. The goal is a new average of at least 80.80.

Six tests averaging 8080 must total 680=480,6\cdot80=480, so the sixth score must be at least 480385=95.480-385=95.

Thus, the correct answer is E.

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