2005 AMC 12B 第 5 题

先试着解答 2005 AMC 12B 第 5 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2005 AMC 12B 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

5.

一个 88 英尺乘 1010 英尺的地面铺满 11 英尺乘 11 英尺的正方形瓷砖。每块瓷砖的图案由四个白色四分之一圆组成,每个圆半径为 12\dfrac12 英尺,圆心在瓷砖的四个角。瓷砖剩余部分为阴影。地面上阴影部分共有多少平方英尺?

An 88-foot by 1010-foot floor is tiled with square tiles of size 11 foot by 11 foot. Each tile has a pattern consisting of four white quarter circles of radius 12\dfrac12 foot centered at each corner of the tile. The remaining portion of the tile is shaded. How many square feet of the floor are shaded?

8020π80 - 20\pi

6010π60 - 10\pi

8010π80 - 10\pi

60+10π60 + 10\pi

80+10π80 + 10\pi

答案:A
知识点:圆面积面积
难度评级:1130
解答:

每块瓷砖的四个四分之一圆合成一个半径为 12\dfrac12 的圆,面积为 π(12)2=π4\pi\left(\dfrac12\right)^2 = \dfrac{\pi}{4}

每块瓷砖阴影面积为 1π41 - \dfrac{\pi}{4}

共有 810=808 \cdot 10 = 80 块瓷砖,所以总阴影面积为 80(1π4)=8020π. 80\left(1 - \dfrac{\pi}{4}\right) = 80 - 20\pi.

所以正确答案是 A

The four quarter circles in a tile together form one full circle of radius 12,\dfrac12, with area π(12)2=π4.\pi\left(\dfrac12\right)^2 = \dfrac{\pi}{4}.

So each tile has shaded area 1π41 - \dfrac{\pi}{4} square feet.

There are 810=808 \cdot 10 = 80 tiles, so the total shaded area is 80(1π4)=8020π. 80\left(1 - \dfrac{\pi}{4}\right) = 80 - 20\pi.

Thus, the correct answer is A.

← 第 4 题#4
完整试卷

其他年份的第 5 题