2024 AMC 12B 第 5 题

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5.

在下面的表达式中,Melanie 把若干个加号改成了减号:

1+3+5+7++97+991 + 3 + 5 + 7 + \cdots + 97 + 99

新表达式求值后为负数。Melanie 至少需要把多少个加号改成减号?

In the following expression, Melanie changed some of the plus signs to minus signs:

1+3+5+7++97+991 + 3 + 5 + 7 + \cdots + 97 + 99

When the new expression was evaluated, it was negative. What is the least number of plus signs that Melanie could have changed to minus signs?

1414

1515

1616

1717

1818

答案:B
知识点:等差数列最优化
难度评级:1340
解答:

原表达式是前 5050 个正奇数之和,等于 502=250050^2 = 2500。把值为 vv 的项从 ++ 改为 -,总和会减少 2v2v,所以要使结果为负,翻号项的和必须大于 25002=1250\dfrac{2500}{2} = 1250

为使项数尽量少,应从 99,97,95,99, 97, 95, \ldots 开始翻号。最大的 kk 个奇数之和为 k(100k)k(100 - k)。当 k=14k = 14 时,1486=1204125014 \cdot 86 = 1204 \le 1250;当 k=15k = 15 时,1585=1275>125015 \cdot 85 = 1275 \gt 1250。所以 1515 个足够,而 1414 个不够。

所以正确答案是 B

The original expression sums the first 5050 odd numbers, giving 502=2500.50^2 = 2500. Changing a term of value vv from ++ to - decreases the total by 2v,2v, so to make the result negative the flipped terms must total more than 25002=1250.\dfrac{2500}{2} = 1250.

To use as few terms as possible, flip the largest odd numbers 99,97,95,99, 97, 95, \ldots The largest kk of them sum to k(100k).k(100 - k). With k=14k = 14 this is 1486=12041250,14 \cdot 86 = 1204 \le 1250, but with k=15k = 15 it is 1585=1275>1250.15 \cdot 85 = 1275 \gt 1250. So 1515 sign changes suffice and 1414 do not.

Thus, the correct answer is B.

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