2017 AMC 12A 第 5 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

5.

在一个 3030 人聚会上,有 2020 个人彼此都认识,还有 1010 个人谁也不认识。彼此认识的人拥抱, 彼此不认识的人握手。一共会发生多少次握手?

At a gathering of 3030 people, there are 2020 people who all know each other and 1010 people who know no one. People who know each other hug, and people who do not know each other shake hands. How many handshakes occur?

240240

245245

290290

480480

490490

答案:B
知识点:图论基本计数
难度评级:1270
解答:

2020 个彼此认识的人只和 1010 个陌生人握手。那 1010 个陌生人中的每个人都和其他 2929 人握手。

把握手次数相加并除以 22(每次握手涉及两个人),得到 12(2010+1029)=12(200+290)=245. \begin{aligned} &\dfrac{1}{2}(20\cdot10+10\cdot29) \\ &=\dfrac{1}{2}(200+290)=245. \end{aligned}

所以正确答案是 B

Each of the 2020 people who know each other shakes hands with only the 1010 strangers. Each of the 1010 strangers shakes hands with all 2929 other people.

Summing handshake counts and dividing by 22 (each handshake involves two people) gives 12(2010+1029)=12(200+290)=245. \begin{aligned} &\dfrac{1}{2}(20\cdot10+10\cdot29) \\ &=\dfrac{1}{2}(200+290)=245. \end{aligned}

Thus, the correct answer is B.

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