2014 AMC 12A 第 5 题

先试着解答 2014 AMC 12A 第 5 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2014 AMC 12A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

5.

一次代数小测中,10%10\% 的学生得 7070 分,35%35\% 得 8080 分,30%30\% 得 9090 分,其余得 100100 分。本次小测成绩的平均数与中位数之差是多少?
On an algebra quiz, 10%10\% of the students scored 7070 points, 35%35\% scored 8080 points, 30%30\% scored 9090 points, and the rest scored 100100 points. What is the difference between the mean and the median of the students’ scores on this quiz?
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答案:C
知识点:平均数中位数(数据)百分数
小提示:
中位数是把所有人成绩排序后处在中间的分数。
The median is the score of the middle student after ordering everyone
大提示:
计算加权平均 0.10(70)+0.35(80)0.10(70)+0.35(80) +0.30(90)+0.25(100)+0.30(90)+0.25(100),再与中位数比较。
Compute the weighted mean 0.10(70)+0.35(80)0.10(70)+0.35(80) +0.30(90)+0.25(100)+0.30(90)+0.25(100) and compare it to the median
解答:
其余 25%25\% 的学生得 100100 分。由于 45%45\% 的学生得分不超过 8080,而 75%75\% 的学生得分不超过 9090,所以中位数是 9090。
平均数为 0.10(70)+0.35(80)+0.30(90)+0.25(100)=7+28+27+25=87。 \begin{aligned} &0.10(70)+0.35(80)\\ &\quad{}+0.30(90)+0.25(100)\\ &\quad{}=7+28+27+25=87 \end{aligned}\text{。}
两者之差为 90−87=390-87=3。
所以正确答案是 C。
The remaining 25%25\% scored 100.100. Since 45%45\% scored at most 8080 and 75%75\% scored at most 90,90, the median is 90.90.
The mean is 0.10(70)+0.35(80)+0.30(90)+0.25(100)=7+28+27+25=87. \begin{aligned} &0.10(70)+0.35(80)\\ &\quad{}+0.30(90)+0.25(100)\\ &\quad{}=7+28+27+25=87. \end{aligned}
The difference is 90−87=3.90-87=3.
Thus, the correct answer is C.
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