1972 AMC 12 第 28 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

28.

将一个直径为 DD 的圆盘放在宽度为 DD8×88\times8 棋盘上,使二者中心重合。被圆盘完全覆盖的棋盘小方格数为:

A circular disc with diameter DD is placed on an 8×88\times8 checkerboard with width DD so that the centers coincide. The number of checkerboard squares which are completely covered by the disc is:

4848

4444

4040

3636

3232

答案:E
知识点:距离公式基本计数
难度评级:2080
小提示:

与棋盘外边界相接的小方格都不可能被完全覆盖

No square touching the outside border can be completely covered

大提示:

在内部的 6×66\times6 个小方格中,单独检查四个角上的方格

Among the 6×66\times6 interior squares, test the four corner squares separately

解答:

边界上的 2828 个小方格没有被完全覆盖。考虑剩余的 6×66\times6 内部网格,并以小方格边长为距离单位,则圆盘半径为 44。该内部网格的四个外角到中心的距离为 32+32=32>4 \sqrt{3^2+3^2}=3\sqrt2\gt4 所以四个角方格未被完全覆盖。其他每个内部方格都在圆盘内:其最远角点到中心的距离至多为 32+22=13<4 \sqrt{3^2+2^2}=\sqrt{13}\lt4\text{。}因此共有 364=3236-4=32 个方格被完全覆盖。

因此,正确答案是 E

The 2828 border squares are not fully covered. Consider the remaining 6×66\times6 interior grid and measure distances in square side lengths, so the disc has radius 4.4. The four outer corners of this interior grid are at distance 32+32=32>4 \sqrt{3^2+3^2}=3\sqrt2\gt4 from the center, so those four corner squares are not fully covered. Every other interior square lies within the disc: its farthest possible corner is at distance at most 32+22=13<4. \sqrt{3^2+2^2}=\sqrt{13}\lt4. Hence 364=3236-4=32 squares are completely covered.

Therefore, the correct answer is E.

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