1956 AMC 12 第 28 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

28.

J 先生将全部遗产留给妻子、女儿、儿子和厨师。女儿与儿子分得遗产的一半,二人所得之比为 4433。妻子所得是儿子的两倍。若厨师得到 $500\$500,则全部遗产为:

Mr. J left his entire estate to his wife, his daughter, his son, and the cook. His daughter and son got half the estate, sharing in the ratio of 44 to 3.3. His wife got twice as much as the son. If the cook received a bequest of $500,\$500, then the entire estate was:

$3500\$3500

$5500\$5500

$6500\$6500

$7000\$7000

$7500\$7500

答案:D
知识点:ratiosestate distribution一次方程
难度评级:1660
小提示:

设女儿和儿子所得分别为 4x4x3x3x

Let the daughter’s and son’s shares be 4x4x and 3x3x

大提示:

他们的 7x7x 是遗产的一半,另一半等于妻子的 6x6x$500\$500

Their 7x7x is half the estate, while the other half is the wife’s 6x6x plus $500\$500

解答:

设女儿得到 4x4x,儿子得到 3x3x。两人共得到 7x7x,即遗产的一半。妻子得到 6x6x,所以由另一半可得 7x=6x+500 7x=6x+500\text{。}因此 x=500x=500,全部遗产为 2(7x)=14(500)=70002(7x)=14(500)=7000 美元。

因此,正确答案是 D

Let the daughter receive 4x4x and the son 3x.3x. Together they receive 7x,7x, which is half the estate. The wife receives 6x,6x, so the other half gives 7x=6x+500. 7x=6x+500. Thus x=500,x=500, and the whole estate is 2(7x)=14(500)=70002(7x)=14(500)=7000 dollars.

Therefore, the correct answer is D.

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