2001 AMC 12 第 1 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

两个数的和是 SS。给每个数都加上 33,再将所得的两个数分别翻倍。最后这两个数的和是多少?

The sum of two numbers is S.S. Suppose 33 is added to each number and then each of the resulting numbers is doubled. What is the sum of the final two numbers?

2S+32S + 3

3S+23S + 2

3S+63S + 6

2S+62S + 6

2S+122S + 12

答案:E
知识点:代数变形分配律
难度评级:950
解答:

给每个数加 33 后,总和从 SS 变为 S+6S + 6。再把每个数翻倍,总和也翻倍,得到 2(S+6)=2S+12. 2(S + 6) = 2S + 12.

因此,正确答案是 E

Adding 33 to each number raises the sum from SS to S+6.S + 6. Doubling each number doubles the sum, giving 2(S+6)=2S+12. 2(S + 6) = 2S + 12.

Thus, the correct answer is E.

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