2017 AMC 12A Problem 1

Below is the professionally curated solution for Problem 1 of the 2017 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:optimizationrate

Difficulty rating: 890

1.

Pablo buys popsicles for his friends. The store sells single popsicles for $1\$1 each, 33-popsicle boxes for $2,\$2, and 55-popsicle boxes for $3.\$3. What is the greatest number of popsicles that Pablo can buy with $8?\$8?

88

1111

1212

1313

1515

Solution:

The cheapest popsicles come from the 55-popsicle box, at $35=$0.60\dfrac{\$3}{5}=\$0.60 each. Even at that rate, 1414 popsicles would cost 14$0.60=$8.40,14\cdot\$0.60=\$8.40, more than $8.\$8.

So Pablo can buy at most 13,13, and he achieves this with two 55-boxes for $6\$6 and one 33-box for $2,\$2, giving 25+3=132\cdot5+3=13 popsicles.

Thus, the correct answer is D.

Problem 1 in Other Years