2013 AMC 12B 第 1 题

先试着解答 2013 AMC 12B 第 1 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2013 AMC 12B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

在一月的某一天,内布拉斯加州 Lincoln 的最高气温比最低气温高 1616 度,最高气温与最低气温的平均值是 3∘3^\circ。这一天 Lincoln 的最低气温是多少度?
On a particular January day, the high temperature in Lincoln, Nebraska, was 1616 degrees higher than the low temperature, and the average of the high and low temperatures was 3∘.3^\circ. In degrees, what was the low temperature in Lincoln that day?
−13-13
−8-8
−5-5
−3-3
1111
答案:C
知识点:平均数一次方程
小提示:
最高和最低相差 1616,所以它们各自离平均值 88 度。
The high and low differ by 16,16, so each is 88 away from their average
大提示:
最低气温比平均值 33 低 88 度。
The low temperature is 88 below the average of 33
解答:
最高气温比最低气温高 1616,所以最低气温比平均值低 88。平均值为 3∘3^\circ,因此最低气温为 3−8=−5∘3 - 8 = -5^\circ。所以正确答案是 C。
The high exceeds the low by 16,16, so the low is 88 below the average. Since the average is 3∘,3^\circ, the low temperature is 3−8=−5∘.3 - 8 = -5^\circ. Thus, the correct answer is C.
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