1967 AMC 12 第 26 题

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26.

若只使用表中信息 103=100010^3=1000104=10,00010^4=10{,}000210=10242^{10}=1024211=20482^{11}=2048212=40962^{12}=4096213=81922^{13}=8192,则关于 log102\log_{10}2 能作出的最强结论是它位于下列哪两个数之间?

If one uses only the tabular information 103=1000,10^3=1000, 104=10,000,10^4=10{,}000, 210=1024,2^{10}=1024, 211=2048,2^{11}=2048, 212=4096,2^{12}=4096, 213=8192,2^{13}=8192, then the strongest statement one can make for log102\log_{10}2 is that it lies between:

310\dfrac3{10}411\dfrac4{11}

310\dfrac3{10} and 411\dfrac4{11}

310\dfrac3{10}412\dfrac4{12}

310\dfrac3{10} and 412\dfrac4{12}

310\dfrac3{10}413\dfrac4{13}

310\dfrac3{10} and 413\dfrac4{13}

310\dfrac3{10}40132\dfrac{40}{132}

310\dfrac3{10} and 40132\dfrac{40}{132}

311\dfrac3{11}40132\dfrac{40}{132}

311\dfrac3{11} and 40132\dfrac{40}{132}

答案:C
知识点:对数不等式极限情形界定
难度评级:1710
小提示:

比较 10310^32102^{10},求下界

Compare 10310^3 with 2102^{10} for a lower bound

大提示:

比较 2132^{13}10410^4,求上界

Compare 2132^{13} with 10410^4 for an upper bound

解答:

103<21010^3\lt2^{10} 可得 3<10log1023\lt10\log_{10}2,所以 log102>310\log_{10}2\gt\frac{3}{10}。由 213<1042^{13}\lt10^4 可得 13log102<413\log_{10}2\lt4,所以 log102<413\log_{10}2\lt\frac{4}{13}。这是表中信息能够推出的选项中最窄的区间。

因此,正确答案是 C

From 103<21010^3\lt2^{10} we get 3<10log102,3\lt10\log_{10}2, so log102>310.\log_{10}2\gt\frac{3}{10}. From 213<1042^{13}\lt10^4 we get 13log102<4,13\log_{10}2\lt4, so log102<413.\log_{10}2\lt\frac{4}{13}. This is the narrowest listed interval justified by the table.

Therefore, the correct answer is C.

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