2017 AIME II 第 1 题

先试着解答 2017 AIME II 第 1 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2017 AIME II 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

求 {1,2,3,4,5,6,7,8}\{1, 2, 3, 4, 5, 6, 7, 8\} 的子集中,有多少个既不是 {1,2,3,4,5}\{1, 2, 3, 4, 5\} 的子集,也不是 {4,5,6,7,8}\{4, 5, 6, 7, 8\} 的子集。
Find the number of subsets of {1,2,3,4,5,6,7,8}\{1, 2, 3, 4, 5, 6, 7, 8\} that are subsets of neither {1,2,3,4,5}\{1, 2, 3, 4, 5\} nor {4,5,6,7,8}.\{4, 5, 6, 7, 8\}.
答案:196
知识点:子集容斥原理
小提示:
计算补集:完全包含在 {1,2,3,4,5}\{1,2,3,4,5\} 中,或完全包含在 {4,5,6,7,8}\{4,5,6,7,8\} 中的子集
Count the complement: subsets that lie entirely inside {1,2,3,4,5}\{1,2,3,4,5\} or entirely inside {4,5,6,7,8}\{4,5,6,7,8\}
大提示:
用容斥,重叠部分是 {4,5}\{4, 5\} 的子集,所以从 282^8 中减去 25+25−222^5 + 2^5 - 2^2
By inclusion-exclusion, the overlap consists of the subsets of {4,5},\{4, 5\}, so subtract 25+25−222^5 + 2^5 - 2^2 from 282^8
解答:
总共有 28=2562^8 = 256 个子集。要排除的是包含在 {1,2,3,4,5}\{1,2,3,4,5\} 中的子集(有 25=322^5 = 32 个),或包含在 {4,5,6,7,8}\{4,5,6,7,8\} 中的子集(也有 3232 个)。同时属于两者的子集正好是交集 {4,5}\{4, 5\} 的子集,共有 22=42^2 = 4 个。
由容斥,不符合条件的子集有 32+32−4=6032 + 32 - 4 = 60 个,因此满足要求的子集有 256−60=196256 - 60 = 196 个。
There are 28=2562^8 = 256 subsets in all. The ones to exclude are those contained in {1,2,3,4,5}\{1,2,3,4,5\} (there are 25=322^5 = 32) or contained in {4,5,6,7,8}\{4,5,6,7,8\} (another 3232). A subset of both is exactly a subset of the intersection {4,5},\{4, 5\}, and there are 22=42^2 = 4 of those.
By inclusion-exclusion, 32+32−4=6032 + 32 - 4 = 60 subsets fail, so 256−60=196256 - 60 = 196 subsets have the required property.
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