2004 AIME II 第 1 题

先试着解答 2004 AIME II 第 1 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2004 AIME II 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

圆的一条弦垂直于一条半径,且交点是这条半径的中点。该弦把圆分成两个区域,较大区域面积与较小区域面积的比可表示为 aπ+bcdπef\frac{a\pi + b\sqrt{c}}{d\pi - e\sqrt{f}}, 其中 aabbccddeeff 都是正整数,aaee 互质,且 ccff 都不被任何质数的平方整除。求 abcdefa \cdot b \cdot c \cdot d \cdot e \cdot f 除以 10001000 的余数。

A chord of a circle is perpendicular to a radius at the midpoint of the radius. The ratio of the area of the larger of the two regions into which the chord divides the circle to the smaller can be expressed in the form aπ+bcdπef,\frac{a\pi + b\sqrt{c}}{d\pi - e\sqrt{f}}, where a,a, b,b, c,c, d,d, e,e, and ff are positive integers, aa and ee are relatively prime, and neither cc nor ff is divisible by the square of any prime. Find the remainder when the product abcdefa \cdot b \cdot c \cdot d \cdot e \cdot f is divided by 1000.1000.

答案:592
知识点:扇形圆面积
难度评级:2050
解答:

按比例缩放,使半径为 22。弦到圆心的距离为 11,所以连到弦两端的半径各与被平分的半径成 6060^\circ 角,两条端点半径形成的圆心角为 120120^\circ。它们截出的等腰三角形面积为 1222sin120=3\frac{1}{2} \cdot 2 \cdot 2 \sin 120^\circ = \sqrt{3},整个圆盘面积为 4π4\pi

较小区域是 120120^\circ 扇形减去该三角形,面积为 4π33\frac{4\pi}{3} - \sqrt{3};较大区域是剩余部分, 面积为 8π3+3\frac{8\pi}{3} + \sqrt{3}。比值为 8π3+34π33=8π+334π33,\frac{\frac{8\pi}{3} + \sqrt{3}}{\frac{4\pi}{3} - \sqrt{3}} = \frac{8\pi + 3\sqrt{3}}{4\pi - 3\sqrt{3}}, 因而 (a,b,c,d,e,f)=(8,3,3,4,3,3)(a, b, c, d, e, f) = (8, 3, 3, 4, 3, 3)

乘积为 833433=25928 \cdot 3 \cdot 3 \cdot 4 \cdot 3 \cdot 3 = 2592,除以 10001000 的余数为 592592

Scale so the radius is 2.2. The chord lies at distance 11 from the center, so each radius to an endpoint of the chord makes a 6060^\circ angle with the bisected radius, and the two endpoint radii form a central angle of 120.120^\circ. The isosceles triangle they cut off has area 1222sin120=3,\frac{1}{2} \cdot 2 \cdot 2 \sin 120^\circ = \sqrt{3}, and the whole disk has area 4π.4\pi.

The smaller region is the 120120^\circ sector minus the triangle, 4π33,\frac{4\pi}{3} - \sqrt{3}, and the larger region is the rest, 8π3+3.\frac{8\pi}{3} + \sqrt{3}. The ratio is 8π3+34π33=8π+334π33,\frac{\frac{8\pi}{3} + \sqrt{3}}{\frac{4\pi}{3} - \sqrt{3}} = \frac{8\pi + 3\sqrt{3}}{4\pi - 3\sqrt{3}}, which has the required form with (a,b,c,d,e,f)=(8,3,3,4,3,3).(a, b, c, d, e, f) = (8, 3, 3, 4, 3, 3).

The product is 833433=2592,8 \cdot 3 \cdot 3 \cdot 4 \cdot 3 \cdot 3 = 2592, whose remainder upon division by 10001000 is 592.592.

完整试卷

其他年份的第 1 题