2010 AMC 12A Problem 21

Below is the professionally curated solution for Problem 21 of the 2010 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 12A solutions, or check the answer key.

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Concepts:polynomialfactoringcompleting the square

Difficulty rating: 2000

21.

The graph of y=x610x5+29x44x3+ax2y=x^6-10x^5+29x^4-4x^3+ax^2 lies above the line y=bx+cy=bx+c except at three values of x,x, where the graph and the line intersect. What is the largest of those values?

44

55

66

77

88

Solution:

Let f(x)f(x) be the graph minus the line. It is nonnegative and vanishes at three points, each a double root, so f(x)=(x3Ax2+BxC)2.f(x)=\big(x^3-Ax^2+Bx-C\big)^2.

Matching coefficients gives 2A=10A=5,-2A=-10\Rightarrow A=5, then A2+2B=29B=2,A^2+2B=29\Rightarrow B=2, then 2C2AB=4C=8.-2C-2AB=-4\Rightarrow C=-8.

Thus the cubic is x35x2+2x+8=(x+1)(x2)(x4),x^3-5x^2+2x+8=(x+1)(x-2)(x-4), with roots 1,2,-1,2, and 4.4. The largest is 4.4.

Thus, A is the correct answer.

Problem 21 in Other Years