2019 AMC 12B Problem 21

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Concepts:Vieta’s Formulascaseworksystem of equations

Difficulty rating: 2220

21.

How many quadratic polynomials with real coefficients are there such that the set of roots equals the set of coefficients? (For clarification: If the polynomial is ax2+bx+c, a0,ax^2+bx+c,\ a\neq0, and the roots are rr and s,s, then the requirement is that {a,b,c}={r,s}.\{a,b,c\}=\{r,s\}.)

33

44

55

66

infinitely many

Solution:

The set {a,b,c}\{a,b,c\} must equal the two-element set {r,s},\{r,s\}, so at least two coefficients coincide, and the roots are the two distinct coefficient values. By Vieta's formulas r+s=bar+s=-\dfrac{b}{a} and rs=ca.rs=\dfrac{c}{a}.

Working through the cases of which coefficients are equal yields the polynomials x2+x2,x^2+x-2, x2x,-x^2-x, x212x12,x^2-\dfrac12 x-\dfrac12, and ux2+1ux+uux^2+\dfrac1u x+u where uu is the unique real root of u3+u+1=0.u^3+u+1=0.

That is 44 polynomials in all.

Thus, B is the correct answer.

Problem 21 in Other Years