1950 AMC 12 第 29 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

29.

某制造商造了一台机器,可在 88 分钟内给 500500 个信封书写地址。他希望再造一台机器,使两台机器同时工作时能在 22 分钟内完成 500500 个信封。若第二台机器单独完成 500500 个信封需要 xx 分钟,则求该时间所用的方程为:

A manufacturer built a machine which will address 500500 envelopes in 88 minutes. He wishes to build another machine so that when both are operating together they will address 500500 envelopes in 22 minutes. The equation used to find how many minutes xx it would require the second machine to address 500500 envelopes alone is:

8x=28-x=2

18+1x=12\dfrac18+\dfrac1x=\dfrac12

5008+500x=500\dfrac{500}{8}+\dfrac{500}{x}=500

x2+x8=1\dfrac{x}{2}+\dfrac{x}{8}=1

以上答案均不正确

None of these answers

答案:B
知识点:速率分式方程
难度评级:1440
小提示:

以每分钟完成多少批 500500 个信封来表示各台机器的效率

Measure each machine’s rate in batches of 500500 envelopes per minute

大提示:

两台机器各自的效率之和等于共同工作的效率

The two individual rates must add to the combined rate

解答:

第一台机器每分钟完成一批 500500 个信封的 18\tfrac18,第二台每分钟完成一批的 1x\tfrac1x。两台一起工作时,每分钟必须完成一批的 12\tfrac12。因此,所需方程为 18+1x=12 \frac18+\frac1x=\frac12\text{。}

因此,正确答案是 B

The first machine completes 18\tfrac18 of a 500500-envelope batch per minute, and the second completes 1x\tfrac1x of a batch per minute. Together they must complete 12\tfrac12 of a batch per minute. Therefore the required equation is 18+1x=12. \frac18+\frac1x=\frac12.

Thus, the correct answer is B.

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