1999 AMC 12 Problem 29

Below is the professionally curated solution for Problem 29 of the 1999 AMC 12, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 12 solutions, or check the answer key.

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Concepts:3D geometryspheregeometric probabilityvolume

Difficulty rating: 2380

29.

A tetrahedron with four equilateral triangular faces has a sphere inscribed within it and a sphere circumscribed about it. For each of the four faces, there is a sphere tangent externally to the face at its center and to the circumscribed sphere. A point PP is selected at random inside the circumscribed sphere. The probability that PP lies inside one of the five small spheres is closest to

00

0.10.1

0.20.2

0.30.3

0.40.4

Solution:

Let OO be the common center of the inscribed and circumscribed spheres. Splitting the tetrahedron into four congruent pieces from OO shows the circumradius is 33 times the inradius, so the circumscribed sphere has 2727 times the inscribed sphere's volume V.V.

Each externally tangent sphere fits between a face and the circumscribed sphere and is congruent to the inscribed sphere, so the five small spheres have total volume 5V.5V. The probability is 5V27V=5270.185,\dfrac{5V}{27V} = \dfrac{5}{27} \approx 0.185, closest to 0.2.0.2.

Thus, the correct answer is C.