2008 AIME I 第 1 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

在参加学校派对的学生中,60%60\% 是女生,40%40\% 喜欢跳舞。后来又来了 2020 名男生,他们都喜欢跳舞,此时派对上的学生中女生占 58%58\%。现在派对上有多少名学生喜欢跳舞?

Of the students attending a school party, 60%60\% of the students are girls, and 40%40\% of the students like to dance. After these students are joined by 2020 more boy students, all of whom like to dance, the party is now 58%58\% girls. How many students now at the party like to dance?

答案:252
知识点:百分数一次方程
难度评级:1750
解答:

设原来派对上有 xx 名学生,则女生有 0.6x0.6x 人,喜欢跳舞的有 0.4x0.4x 人。 2020 名男生到来后,女生人数不变,总人数变为 x+20x + 20,所以 0.6x=0.58(x+20)0.6x = 0.58(x + 20)。于是 0.02x=11.60.02x = 11.6,得 x=580x = 580

现在喜欢跳舞的学生人数为 0.4580+20=232+20=2520.4 \cdot 580 + 20 = 232 + 20 = 252

Let xx be the number of students originally at the party, so 0.6x0.6x are girls and 0.4x0.4x like to dance. When the 2020 boys arrive, the number of girls is unchanged but the total becomes x+20,x + 20, so 0.6x=0.58(x+20).0.6x = 0.58(x + 20). Then 0.02x=11.6,0.02x = 11.6, giving x=580.x = 580.

The number of students who now like to dance is 0.4580+20=232+20=252.0.4 \cdot 580 + 20 = 232 + 20 = 252.

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