2004 AIME I 第 3 题

先试着解答 2004 AIME I 第 3 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2004 AIME I 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

3.

一个凸多面体 PP2626 个顶点、6060 条边和 3636 个面,其中 2424 个是三角形, 1212 个是四边形。空间对角线是连接两个不相邻且不属于同一个面的顶点的线段。 PP 有多少条空间对角线?

A convex polyhedron PP has 2626 vertices, 6060 edges, and 3636 faces, 2424 of which are triangular, and 1212 of which are quadrilaterals. A space diagonal is a line segment connecting two non-adjacent vertices that do not belong to the same face. How many space diagonals does PP have?

答案:241
知识点:多面体对角线补集计数
难度评级:2070
解答:

任意一对顶点恰好决定三类对象之一:一条边、一个面的对角线,或一条空间对角线。顶点对总数为 (262)=325\binom{26}{2} = 325

其中 6060 对是边。2424 个三角形面没有对角线,而 1212 个四边形面各有 22 条对角线,共 2424 条面对角线(由于多面体是凸的,没有两个面会共享同一条对角线)。

空间对角线的条数为 3256024=241325 - 60 - 24 = 241

Every pair of vertices determines exactly one of three things: an edge, a diagonal of a face, or a space diagonal. There are (262)=325\binom{26}{2} = 325 pairs of vertices in all.

Of these, 6060 are edges. The 2424 triangular faces have no diagonals, while each of the 1212 quadrilateral faces has 2,2, for 2424 face diagonals (no two faces share a diagonal, since the polyhedron is convex).

The number of space diagonals is 3256024=241.325 - 60 - 24 = 241.

← 第 2 题#2
完整试卷

其他年份的第 3 题