2007 AIME I Problem 3

Below is the professionally curated solution for Problem 3 of the 2007 AIME I, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AIME I solutions, or check the answer key.

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Concepts:complex numberbinomial theorem

Difficulty rating: 1970

3.

The complex number zz is equal to 9+bi,9 + bi, where bb is a positive real number and i2=1.i^2 = -1. Given that the imaginary parts of z2z^2 and z3z^3 are equal, find b.b.

Solution:

By the binomial theorem, z2=(81b2)+18biz^2 = (81 - b^2) + 18bi and z3=(72927b2)+(243bb3)i.z^3 = (729 - 27b^2) + (243b - b^3)i. Setting the imaginary parts equal gives 18b=243bb3.18b = 243b - b^3.

Since bb is positive we may divide by b,b, leaving b2=24318=225,b^2 = 243 - 18 = 225, so b=15.b = 15.

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