2002 AIME II 第 4 题

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4.

用边长为 11 个单位的正六边形庭院砖围出一个花园,砖块边对边摆放,每一边有 nn 块。 图示为 n=5n = 5 时围绕花园的砖块路径。

n=202n = 202,则路径围成的花园面积(不包括路径本身)为 m(3/2)m\left(\sqrt{3}/2\right) 平方单位,其中 mm 是正整数。求 mm 除以 10001000 的余数。

Patio blocks that are regular hexagons 11 unit on a side are used to outline a garden by placing the blocks edge to edge with nn on each side. The diagram indicates the path of blocks around the garden when n=5.n = 5.

If n=202,n = 202, then the area of the garden enclosed by the path, not including the path itself, is m(3/2)m\left(\sqrt{3}/2\right) square units, where mm is a positive integer. Find the remainder when mm is divided by 1000.1000.

答案:803
知识点:正多边形求和面积分割
难度评级:2340
解答:

由路径围成的花园本身是一个单位六边形阵列,每边有 n1n - 1 个六边形。从中心向外按 6,12,6, 12, \ldots 个六边形的环来计数,它包含 1+6+12++6(n2)=1+3(n2)(n1) \begin{aligned} &1 + 6 + 12 + \cdots + 6(n-2) \\ &= 1 + 3(n-2)(n-1) \end{aligned} 个小六边形。取 n=202n = 202,得到 1+3200201=1206011 + 3 \cdot 200 \cdot 201 = 120601 个。

每个单位六边形由 66 个边长为 11 的等边三角形组成,所以面积为 634=3326 \cdot \frac{\sqrt{3}}{4} = 3 \cdot \frac{\sqrt{3}}{2}。因此花园面积是 3120601=3618033 \cdot 120601 = 361803 倍的 32\frac{\sqrt{3}}{2},所以 m=361803m = 361803,除以 10001000 的余数为 803803

The garden enclosed by the path is itself a hexagonal arrangement of unit hexagons with n1n - 1 on each side. Counting from the center outward in rings of 6,12,6, 12, \ldots hexagons, it contains 1+6+12++6(n2)=1+3(n2)(n1) \begin{aligned} &1 + 6 + 12 + \cdots + 6(n-2) \\ &= 1 + 3(n-2)(n-1) \end{aligned} blocks, which for n=202n = 202 is 1+3200201=120601.1 + 3 \cdot 200 \cdot 201 = 120601.

Each unit hexagon consists of 66 equilateral triangles of side 1,1, so its area is 634=332.6 \cdot \frac{\sqrt{3}}{4} = 3 \cdot \frac{\sqrt{3}}{2}. The garden's area is therefore 3120601=3618033 \cdot 120601 = 361803 times 32,\frac{\sqrt{3}}{2}, so m=361803,m = 361803, and the remainder upon division by 10001000 is 803.803.

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