Question

Si $\angle CBD$ es un ángulo recto, entonces este transportador indica que la medida de $\angle ABC$ es aproximadamente

If $\angle CBD$ is a right angle, then this protractor indicates that the measure of $\angle ABC$ is approximately

$20^\circ$

$40^\circ$

$50^\circ$

$70^\circ$

$120^\circ$

Leyendo el transportador, el rayo $BA$ está cerca de $20^\circ$ y el rayo $BD$ está cerca de $160^\circ.$

Como $\angle CBD$ es un ángulo recto, el rayo $BC$ está en $160^\circ - 90^\circ = 70^\circ.$

Entonces $\angle ABC = 70^\circ - 20^\circ = 50^\circ.$

Por lo tanto, la respuesta correcta es C.

Reading the protractor, ray $BA$ is at about $20^\circ$ and ray $BD$ is at about $160^\circ.$

Because $\angle CBD$ is a right angle, ray $BC$ is at $160^\circ - 90^\circ = 70^\circ.$

Therefore $\angle ABC = 70^\circ - 20^\circ = 50^\circ.$

Thus, the correct answer is C .