2026 AIME II 第 2 题

先试着解答 2026 AIME II 第 2 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2026 AIME II 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

2.

下图是一排 1010 个正方形组成的网格。每个正方形都有一条从左下顶点连到右上顶点的对角线。 一只虫子沿线段从顶点走到顶点,永不经过同一条线段两次,并且在水平线段或对角线段上绝不从右向左走。 设 NN 为虫子从左下角 (A)(A) 走到右上角 (B)(B) 的路径数。图中粗线段展示了一条从 AABB 的路径。求 N\sqrt{N}

The figure below shows a grid of 1010 squares in a row. Each square has a diagonal connecting its lower left vertex to its upper right vertex. A bug moves along the line segments from vertex to vertex, never traversing the same segment twice and never moving from right to left along a horizontal or diagonal segment. Let NN be the number of paths the bug can take from the lower left corner (A)(A) to the upper right corner (B).(B). One such path from AA to BB is shown by the thick line segments in the figure. Find N.\sqrt{N}.

答案:243
知识点:格路乘法原理
难度评级:2230
解答:

A=(0,0)A = (0, 0)B=(10,1)B = (10, 1)。每次水平或对角移动都向右,所以虫子的 xx 坐标 从不减小;它会恰好一次穿过每个 1010 个竖条,并在相应正方形的三条向右线段中选一条: 底边、顶边、或对角线。

这十个选择决定整条路径。每次穿越会以确定的高度到达(底边到低处,顶边或对角线到高处),也以 确定的高度离开(底边或对角线从低处,顶边从高处),所以在每条竖直线上,虫子恰好在到达高度和离开 高度不同时走那条竖直线段;每条竖直线段至多需要一次,因此不会重复线段。两端同理:虫子从 AA 的低处开始,到 BB 的高处结束,必要时使用端点处的竖直线段。反过来,每串选择都给出一条 合法路径。

因此 N=310N = 3^{10},且 N=35=243\sqrt{N} = 3^5 = 243

Put A=(0,0)A = (0, 0) and B=(10,1).B = (10, 1). Every horizontal and diagonal move goes rightward, so the bug's xx-coordinate never decreases, and it crosses each of the 1010 vertical strips exactly once, using exactly one of that square's three rightward segments: the bottom edge, the top edge, or the diagonal.

These ten choices determine the whole path. Each crossing arrives at a definite height (bottom edge: low; top edge or diagonal: high) and departs at a definite height (bottom edge or diagonal: low; top edge: high), so at each vertical line the bug traverses the vertical segment exactly when the arrival and departure heights differ — and each vertical segment is needed at most once, so no segment repeats. The same applies at the ends: the bug starts low at AA and finishes high at B,B, using the end verticals if necessary. Conversely, every sequence of choices yields a valid path.

Therefore N=310,N = 3^{10}, and N=35=243.\sqrt{N} = 3^5 = 243.

← 第 1 题#1
完整试卷

其他年份的第 2 题