2009 AIME I 第 11 题

先试着解答 2009 AIME I 第 11 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2009 AIME I 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

11.

考虑所有三角形 OPQOPQ,其中 OO 是原点,PPQQ 是平面上互不相同的点,且坐标为非负整数 (x,y)(x, y),满足 41x+y=200941x + y = 2009。求这些不同三角形中,面积为正整数的个数。

Consider the set of all triangles OPQOPQ where OO is the origin and PP and QQ are distinct points in the plane with nonnegative integer coordinates (x,y)(x, y) such that 41x+y=2009.41x + y = 2009. Find the number of such distinct triangles whose area is a positive integer.

答案:600
知识点:格点鞋带公式奇偶性
难度评级:2840
解答:

直线上非负整数坐标的点为 Pi=(i,200941i)P_i = (i,\, 2009 - 41i),其中 i=0,1,,49i = 0, 1, \ldots, 49,共五十个点。若 P=PiP = P_iQ=PjQ = P_j, 用鞋带公式得 [OPQ]=12i(200941j)j(200941i)=20092ij. \begin{aligned} [OPQ] &= \small \frac{1}{2}\left|\,i(2009 - 41j) - j(2009 - 41i)\,\right| \\ &= \frac{2009}{2}\,|i - j|. \end{aligned}

对互不相同的点,面积自动为正;又因为 20092009 是奇数,它是整数当且仅当 iji - j 为偶数,也就是 iijj 同奇偶。偶数编号有 2525 个,奇数编号也有 2525 个,所以三角形个数为 (252)+(252)=300+300=600.\binom{25}{2} + \binom{25}{2} = 300 + 300 = 600.

The points on the line with nonnegative integer coordinates are Pi=(i,200941i)P_i = (i,\, 2009 - 41i) for i=0,1,,49i = 0, 1, \ldots, 49 — fifty points in all. For P=PiP = P_i and Q=Pj,Q = P_j, the shoelace formula gives [OPQ]=12i(200941j)j(200941i)=20092ij. \begin{aligned} [OPQ] &= \small \frac{1}{2}\left|\,i(2009 - 41j) - j(2009 - 41i)\,\right| \\ &= \frac{2009}{2}\,|i - j|. \end{aligned}

This is automatically positive for distinct points, and since 20092009 is odd, it is an integer exactly when iji - j is even, that is, when ii and jj have the same parity. There are 2525 even and 2525 odd indices, so the number of triangles is (252)+(252)=300+300=600.\binom{25}{2} + \binom{25}{2} = 300 + 300 = 600.

← 第 10 题#10
完整试卷

其他年份的第 11 题