1956 AMC 12 第 32 题
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所有题目均经美国数学协会（MAA）官方合法授权使用。
32.
乔治和亨利从游泳池的两端同时开始比赛。一分半后，他们在泳池中央相遇。若两人转身都不耽搁，并各自保持原来的速度，那么从出发起多少分钟后他们会第二次相遇？
George and Henry started a race from opposite ends of the pool. After a minute and a half, they passed each other in the center of the pool. If they lost no time in turning and maintained their respective speeds, how many minutes after starting did they pass each other the second time?
答案：B
小提示：
第一次在中央相遇，说明两名游泳者的速度相同
Meeting at the center means the two swimmers have equal speeds
大提示：
他们在 分钟时分别到达对岸，转身后各自还要游半个泳池的长度
They reach the opposite ends at minutes, turn, and need another half-pool each
解答：
因为他们从两端同时出发并在中央第一次相遇，所以两人的速度相同。每个人都在 分钟后到达对岸。他们立即转身，各自再用 分钟回到中央并再次相遇。第二次相遇发生在出发 分钟后。
因此，正确答案是 B。
Because they started simultaneously from opposite ends and first met at the center, their speeds are equal. Each reaches the opposite end after minutes. They turn immediately, and each then needs another minutes to return to the center, where they meet again. The second meeting occurs after minutes.
Thus, the correct answer is B.
其他年份的第 32 题
1950 AMC 12 · 1951 AMC 12 · 1952 AMC 12 · 1953 AMC 12 · 1954 AMC 12 · 1955 AMC 12 · 1957 AMC 12 · 1958 AMC 12 · 1959 AMC 12 · 1960 AMC 12 · 1961 AMC 12 · 1962 AMC 12 · 1963 AMC 12 · 1964 AMC 12 · 1965 AMC 12 · 1966 AMC 12 · 1967 AMC 12 · 1968 AMC 12 · 1969 AMC 12 · 1970 AMC 12 · 1971 AMC 12 · 1972 AMC 12 · 1973 AMC 12