1955 AMC 12 第 32 题

先试着解答 1955 AMC 12 第 32 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1955 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

32.

若 ax2+2bx+c=0ax^2+2bx+c=0 的判别式为零,则关于 aa、bb 和 cc 的另一个正确结论是:
If the discriminant of ax2+2bx+c=0ax^2+2bx+c=0 is zero, then another true statement about a,a, b,b, and cc is that:
它们构成等差数列
they form an arithmetic progression
它们构成等比数列
they form a geometric progression
它们互不相等
they are unequal
它们全是负数
they are all negative numbers
只有 bb 为负数,而 aa 和 cc 为正数
only bb is negative and aa and cc are positive
答案:B
知识点:quadratic discriminantgeometric progression
小提示:
令 (2b)2−4ac(2b)^2-4ac 等于零
Set (2b)2−4ac(2b)^2-4ac equal to zero
大提示:
将所得关系与等差数列和等比数列的判定条件比较
Compare the resulting relation with the defining tests for arithmetic and geometric progressions
解答:
判别式为零给出 (2b)2−4ac=0, (2b)^2-4ac=0\text{,}因而 b2=acb^2=ac。等价地,在比值有定义时,ab=bc\frac{a}{b}=\frac{b}{c},这正是 a,b,ca,b,c 构成等比数列的条件。
因此,正确答案是 B。
A zero discriminant gives (2b)2−4ac=0, (2b)^2-4ac=0, hence b2=ac.b^2=ac. Equivalently, ab=bc\frac{a}{b}=\frac{b}{c} where the ratios are defined, which is the defining relation for a,b,ca,b,c to form a geometric progression.
Thus, the correct answer is B.
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.