2016 AMC 10A Problem 10

Below is the professionally curated solution for Problem 10 of the 2016 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10A solutions, or check the answer key.

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Concepts:areaarithmetic sequence

Difficulty rating: 1370

10.

A rug is made with three different colors as shown. The areas of the three differently colored regions form an arithmetic progression. The inner rectangle is one foot wide, and each of the two outer regions are 11 foot wide on all four sides. What is the length in feet of the inner rectangle?

11

22

44

66

88

Solution:

Let ll be the length of the inner rectangle. Then the area of the inner rectangle is l.l.

The area of the middle region is going to be (l+2)3l=2l+6. (l + 2) \cdot 3 - l = 2l + 6. The area of the outer region is (l+4)5(l+2)3=2l+14. (l + 4) \cdot 5 - (l + 2) \cdot 3 = 2l + 14.

We know that these 33 values form an arithmetic sequence. That means that l+2l+14=2(2l+6)3l+14=4l+12l=2\begin{align*} l + 2l + 14 &= 2(2l + 6) \\ 3l + 14 &= 4l + 12 \\ l &= 2\end{align*}

Thus, the correct answer is B .

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