2015 AMC 10B Problem 10

Below is the professionally curated solution for Problem 10 of the 2015 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 10B solutions, or check the answer key.

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Concepts:units digitparity

Difficulty rating: 960

10.

What are the sign and units digit of the product of all the odd negative integers strictly greater than 2015?-2015?

It is a negative number ending with a 1.

It is a positive number ending with a 1.

It is a negative number ending with a 5.

It is a positive number ending with a 5.

It is a negative number ending with a 0.

Solution:

There are 10071007 odd numbers greater than 2015.-2015.

Our product is of an odd number of negative numbers, so the result is negative.

Also, we multiply by 5-5 in there, so the product is a multiple of 5,5, making it end in 55 or 0.0. None of our factors are even, so the product can't be even.

Therefore, the product must end in 5.5.

Thus, the correct answer is C .

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