Question

一支篮球队两分球命中率为 $50\%$ ，三分球命中率为 $40\%$ ，共得到 $54$ 分。他们两分球出手次数比三分球多 $50\%$ 。他们出手了多少次三分球？

A basketball team’s players were successful on $50\%$ of their two-point shots and $40\%$ of their three-point shots, which resulted in $54$ points. They attempted $50\%$ more two-point shots than three-point shots. How many three-point shots did they attempt?

$10$

$15$

$20$

$25$

$30$

答案：C

知识点：百分数一次方程

难度评级：1280

小提示：

设三分球出手次数为 $x$ 。

Let $x$ be the number of three-point attempts

大提示：

用 $x$ 表示两类投篮的总得分。

Translate made-shot percentages into total points in terms of $x$

解答：

设三分球出手 $t$ 次。

三分球命中 $0.4 t$ 次，得分为 $1.2t$ 。

两分球出手 $1.5t$ 次，命中 $0.75t$ 次，得分为 $1.5t$ 。

因此总分满足 $2.7t=54\text{，}$ 所以 $t=20$ 。

所以正确答案是 C。

Let $t$ be the number of three-point attempts.

The number of made three-point shots is $0.4 t,$ giving $1.2t$ points.

The number of two-point attempts is $1.5t,$ so the number made is $0.75t,$ giving $1.5t$ points.

Thus the total number of points satisfies $2.7t=54,$ so $t=20.$

Thus, the correct answer is C.

2013 AMC 10B 第 10 题

答案：C

难度评级：1280

小提示：

大提示：

解答：

其他年份的第 10 题