2008 AMC 10B 第 23 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

23.

一个矩形地板尺寸为 aa 英尺乘 bb 英尺,其中 aabb 是正整数且 b>ab\gt a。一位艺术家在地板上画一个矩形,画出的矩形边与地板边平行。未涂色部分在画出的矩形周围形成宽 11 英尺的边框,并占整个地板面积的一半。有多少个有序对 (a,b)(a,b) 满足条件?

A rectangular floor measures aa feet by bb feet, where aa and bb are positive integers with b>a.b\gt a. An artist paints a rectangle on the floor with the sides of the rectangle parallel to the sides of the floor. The unpainted part of the floor forms a border of width 11 foot around the painted rectangle and occupies half the area of the entire floor. How many possibilities are there for the ordered pair (a,b)?(a,b)?

11

22

33

44

55

答案:B
知识点:西蒙最爱的因式分解技巧丢番图方程面积
难度评级:1580
解答:

被涂色矩形为 (a2)×(b2)(a-2)\times(b-2),且是地板面积的一半,所以 ab=2(a2)(b2)ab=2(a-2)(b-2)

展开得 0=ab4a4b+80=ab-4a-4b+8,两边加 88(a4)(b4)=8(a-4)(b-4)=8

b>a>0b\gt a\gt 0 下,分解 8=18=248=1\cdot 8=2\cdot 4,得到 (a,b)=(5,12)(a,b)=(5,12)(6,8)(6,8),所以共有 22 种可能。

所以正确答案是 B

The painted rectangle is (a2)×(b2),(a-2)\times(b-2), and it is half the floor, so ab=2(a2)(b2).ab=2(a-2)(b-2).

Expanding gives 0=ab4a4b+8,0=ab-4a-4b+8, and adding 88 yields (a4)(b4)=8.(a-4)(b-4)=8.

With b>a>0,b\gt a\gt 0, the factorizations 8=18=248=1\cdot 8=2\cdot 4 give (a,b)=(5,12)(a,b)=(5,12) and (6,8).(6,8). So there are 22 possibilities.

Thus, the correct answer is B.

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