2006 AMC 10B 第 23 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

23.

一个三角形被从两个顶点向对边作出的两条线分割成三个三角形和一个四边形。如图,三个三角形面积分别为 337777。阴影四边形的面积是多少?

A triangle is partitioned into three triangles and a quadrilateral by drawing two lines from vertices to their opposite sides. The areas of the three triangles are 3,3, 7,7, and 7,7, as shown. What is the area of the shaded quadrilateral?

1515

1717

352\dfrac{35}{2}

1818

553\dfrac{55}{3}

答案:D
知识点:面积比方程组
难度评级:1950
解答:

将四边形分成两个面积为 RRSS 的三角形,则阴影面积为 T=R+ST=R+S

比较共高三角形,由底边比得到 R3=T+710\tfrac{R}{3}=\tfrac{T+7}{10}S7=T+314\tfrac{S}{7}=\tfrac{T+3}{14}

因此 所以 10T=3(T+7)10T=3(T+7) +5(T+3)+5(T+3) =8T+36=8T+36,得到 T=18T=18T=R+S=3T+710+7T+314,T=R+S=3\cdot\tfrac{T+7}{10}+7\cdot\tfrac{T+3}{14},

所以正确答案是 D

Split the quadrilateral into two triangles of areas RR and S,S, so the shaded area is T=R+S.T=R+S.

Comparing triangles that share an altitude, base ratios give R3=T+710\tfrac{R}{3}=\tfrac{T+7}{10} and S7=T+314.\tfrac{S}{7}=\tfrac{T+3}{14}.

Then T=R+S=3T+710+7T+314,T=R+S=3\cdot\tfrac{T+7}{10}+7\cdot\tfrac{T+3}{14}, so 10T=3(T+7)10T=3(T+7) +5(T+3)+5(T+3) =8T+36,=8T+36, giving T=18.T=18.

Thus, the correct answer is D.

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