2016 AMC 10B Problem 6

Below is the professionally curated solution for Problem 6 of the 2016 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.

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Concepts:digitsextremal argument

Difficulty rating: 960

6.

Laura added two three-digit positive integers. All six digits in these numbers are different. Laura's sum is a three-digit number S.S. What is the smallest possible value for the sum of the digits of S?S?

 1 \ 1

 4 \ 4

 5 \ 5

 15 \ 15

 21 \ 21

Solution:

The smallest possible sum of two three-digit numbers with six distinct digits is at least 104+235=339104+235=339. Any three-digit number at least 339339 with digit sum less than 44 would have to be one of 100,101,110,200,201,210,300,301,310100,101,110,200,201,210,300,301,310, all of which are less than 339339. So the digit sum of SS is at least 44.

The example 157+243=400157+243=400 uses six distinct digits and has digit sum 44. Thus the smallest possible digit sum is 44.

Thus, the correct answer is B.

Problem 6 in Other Years