2009 AMC 10A Problem 6

Below is the professionally curated solution for Problem 6 of the 2009 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

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Concepts:circle area tangent circles

Difficulty rating: 1020

A circle of radius $2$ is inscribed in a semicircle, as shown. The area inside the semicircle but outside the circle is shaded. What fraction of the semicircle's area is shaded?

$\dfrac{1}{2}$

$\dfrac{\pi}{6}$

$\dfrac{2}{\pi}$

$\dfrac{2}{3}$

$\dfrac{3}{\pi}$

Solution:

The inscribed circle rests on the diameter and is tangent to the arc, so the semicircle has radius $4.$ Its area is $\dfrac12 \pi (4)^2 = 8\pi.$

The circle's area is $\pi(2)^2 = 4\pi,$ so the shaded area is $8\pi - 4\pi = 4\pi.$

The shaded fraction is $\dfrac{4\pi}{8\pi} = \dfrac12.$

Thus, the correct answer is A.

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