2008 AMC 10A Problem 6

Below is the professionally curated solution for Problem 6 of the 2008 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 10A solutions, or check the answer key.

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Concepts:distance rate and timeharmonic mean

Difficulty rating: 1100

6.

A triathlete competes in a triathlon in which the swimming, biking, and running segments are all of the same length. The triathlete swims at a rate of 33 kilometers per hour, bikes at a rate of 2020 kilometers per hour, and runs at a rate of 1010 kilometers per hour. Which of the following is closest to the triathlete's average speed, in kilometers per hour, for the entire race?

33

44

55

66

77

Solution:

Let each segment have length x.x. The total time is x3+x20+x10=2960x \dfrac{x}{3} + \dfrac{x}{20} + \dfrac{x}{10} = \dfrac{29}{60}x hours for the distance 3x.3x.

The average speed is 3x2960x=180296.2,\dfrac{3x}{\frac{29}{60}x} = \dfrac{180}{29} \approx 6.2, which is closest to 6.6.

Thus, the correct answer is D.

Problem 6 in Other Years