2025 AMC 10B 第 23 题

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23.

一个由小正方形组成的矩形网格有 141141 行和 9191 列。每个小正方形里有放两个数字的空间。Horace 和 Vera 都把从 11141×91=12,831141 \times 91 = 12{,}831 的数字填入网格。Horace 按行填写:他把 119191 依次从左到右填入第 11 行,把 9292182182 依次从左到右填入第 22 行,并如此继续到第 141141 行。Vera 按列填写:她把 11141141 依次从上到下填入第 11 列,再把 142142282282 依次从上到下填入第 22 列,并如此继续到第 9191 列。有多少个小正方形中两人写下了相同的数字?

A rectangular grid of squares has 141141 rows and 9191 columns. Each square has room for two numbers. Horace and Vera each fill in the grid by putting the numbers from 11 through 141×91=12,831141 \times 91 = 12{,}831 into the squares. Horace fills the grid horizontally: he puts 11 through 9191 in order from left to right into row 1,1, puts 9292 through 182182 into row 22 in order from left to right, and continues similarly through row 141.141. Vera fills the grid vertically: she puts 11 through 141141 in order from top to bottom into column 1,1, then 142142 through 282282 into column 22 in order from top to bottom, and continues similarly through column 91.91. How many squares get two copies of the same number?

77

1010

1111

1212

1919

答案:C
知识点:丢番图方程模运算
难度评级:2300
解答:

在第 ii 行第 jj 列,Horace 写的是 91(i1)+j91(i - 1) + j,Vera 写的是 141(j1)+i141(j - 1) + i。令二者相等并化简,得到 9i14j=59i - 14j = -5,所以 i=14j59i = \tfrac{14j - 5}{9},恰好在 j1(mod9)j \equiv 1 \pmod 9 时为整数。对于 j=1,10,19,,91j = 1, 10, 19, \ldots, 91,共有 1111 个值,且对应的 ii1,15,29,,1411, 15, 29, \ldots, 141,都在范围内。因此有 1111 个小正方形匹配,正确答案是 C

At row i,i, column j,j, Horace writes 91(i1)+j91(i - 1) + j and Vera writes 141(j1)+i.141(j - 1) + i. Set them equal and simplify to get 9i14j=5,9i - 14j = -5, so i=14j59,i = \tfrac{14j - 5}{9}, an integer exactly when j1(mod9).j \equiv 1 \pmod 9. For j=1,10,19,,91,j = 1, 10, 19, \ldots, 91, that's 1111 values, and ii runs 1,15,29,,141,1, 15, 29, \ldots, 141, all within range. So 1111 squares match. Thus, C is the correct answer.

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