2018 AMC 10A Problem 16

Below is the professionally curated solution for Problem 16 of the 2018 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:right trianglealtitudecounting integers in a range

Difficulty rating: 1540

16.

Right triangle ABCABC has leg lengths AB=20AB=20 and BC=21.BC=21. Including AB\overline{AB} and BC,\overline{BC}, how many line segments with integer length can be drawn from vertex BB to a point on hypotenuse AC?\overline{AC}?

55

88

1212

1313

1515

Solution:

Let PP be the foot of the altitude from BB to AC.\overline{AC}. We also get that AC=29.AC = 29.

This tells us that 29PB2=20212 \dfrac{29 \cdot PB}{2} = \dfrac{20 \cdot 21}{2}PB=202129, PB = \dfrac{20 \cdot 21}{29}, by calculating the area in two ways. This value is between 1414 and 15.15.

Note that as we move the line segment from AB\overline{AB} to PB,\overline{PB}, the line segment's length ranges from ABAB to PB.PB.

The integer values it covers therefore goes from 2020 to 15.15. Similarly, as the line segment moves from PB\overline{PB} to CB,\overline{CB}, its takes on the values from 1515 to 21.21.

This gives us 1313 unique line segments that have an integer value length.

Thus, D is the correct answer.

Problem 16 in Other Years