2016 AMC 10B Problem 1

Below is the professionally curated solution for Problem 1 of the 2016 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.

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Concepts:exponentsubstitution

Difficulty rating: 770

1.

What is the value of 2a1+a12a\dfrac{2a^{-1}+\frac{a^{-1}}{2}}{a} when a=12?a= \tfrac{1}{2}?

 1 \ 1

 2 \ 2

 52 \ \dfrac{5}{2}

 10 \ 10

 20 \ 20

Solution:

The expression is equivalent to 2a2+a22=2.5(a1)2.2a^{-2}+\frac{a^{-2}}{2} = 2.5 (a^{-1})^2. Then a1a^{-1} is equal to 112=2,\dfrac{1}{\frac 12} = 2, so our expression is equal to 2.522=10.2.5\cdot 2^2 = 10.

Thus, the correct answer is D .

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