2016 AMC 10B Problem 1

Attempt Problem 1 of the 2016 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.

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1.

What is the value of 2a−1+a−12a\dfrac{2a^{-1}+\frac{a^{-1}}{2}}{a} when a=12?a= \tfrac{1}{2}?

 1 \ 1

 2 \ 2

 52 \ \dfrac{5}{2}

 10 \ 10

 20 \ 20

Answer: D
Concepts:exponentsubstitution
Difficulty rating: 770
Small Hint:

Substitute a=12a=\frac{1}{2} after combining powers of aa

Big Hint:

Dividing by aa turns a−1a^{-1} into a−2a^{-2}

Solution:

The expression is equivalent to 2a−2+a−22=2.5(a−1)2.2a^{-2}+\frac{a^{-2}}{2} = 2.5 (a^{-1})^2. Then a−1a^{-1} is equal to 112=2,\dfrac{1}{\frac 12} = 2, so our expression is equal to 2.5⋅22=10.2.5\cdot 2^2 = 10.

Thus, the correct answer is D .

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