2010 AMC 10A Problem 1 — Solution | LIVE by Po-Shen Loh

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2010 AMC 10A Problem 1

Below is the professionally curated solution for Problem 1 of the 2010 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:mean decimal

Difficulty rating: 560

1.

Mary's top book shelf holds five books with the following widths, in centimeters: $6,$ $\dfrac{1}{2},$ $1,$ $2.5,$ and $10.$

What is the average book width, in centimeters?

$1$

$2$

$3$

$4$

$5$

Solution:

Adding the five widths gives $6+\dfrac12+1+2.5+10=20.$ The average is $20\div5=4.$

Thus, D is the correct answer.

Full Exam Problem 2 →

Problem 1 in Other Years

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