2018 AMC 10A Problem 1

Attempt Problem 1 of the 2018 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10A solutions, or check the answer key.

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1.

What is the value of (((2+1)1+1)1+1)1+1?\left(\left((2+1)^{-1}+1\right)^{-1}+1\right)^{-1}+1?

58\dfrac{5}{8}

117\dfrac{11}{7}

85\dfrac{8}{5}

1811\dfrac{18}{11}

158\dfrac{15}{8}

Answer: B
Concepts:fractionorder of operations
Difficulty rating: 560
Small Hint:

Work from the innermost reciprocal outward

Big Hint:

After each reciprocal step, simplify before adding the next 11

Solution:

We can simplify this as follows. (((2+1)1+1)1+1)1+1=((13+1)1+1)1+1=(34+1)1+1=47+1=117 \begin{aligned} &\left(\left((2+1)^{-1}+1\right)^{-1}+1\right)^{-1}+1 \\ &=\left(\left(\dfrac{1}{3}+1\right)^{-1}+1\right)^{-1}+1 \\ &=\left(\dfrac{3}{4}+1\right)^{-1}+1 \\ &=\dfrac{4}{7} + 1 \\ &=\dfrac{11}{7} \end{aligned}

Thus, B is the correct answer.

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