2021 AMC 10A Fall Problem 1

Attempt Problem 1 of the 2021 AMC 10A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Fall solutions, or check the answer key.

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1.

What is the value of the following expression?

(21122021)2169\dfrac{(2112-2021)^2}{169}

77

2121

4949

6464

9191

Answer: C
Concepts:fractionexponent
Difficulty rating: 450
Small Hint:

21122021=91=7132112-2021=91=7\cdot13

Big Hint:

The denominator is 13213^2

Solution:

Since 21122021=91=713,2112-2021=91=7\cdot13, (21122021)2169=(713)2132=72=49. \begin{aligned} \frac{(2112-2021)^2}{169} &=\frac{(7\cdot13)^2}{13^2}\\ &=7^2=49. \end{aligned}

Thus, C is the correct answer.

Full Exam

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